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https://github.com/micropython/micropython.git
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e73cf71a24
This commit fixes a test failure for `extmod/re_sub.py` where the code, whilst being correct, would not make the test pass due to a newer Python version than expected. On Python 3.13, running `tests/extmod/re_sub.py` would yield a deprecation warning about `re.sub` not providing the match count as a keyword parameter. This warning would be embedded in the expected test result and thus the test would always fail. Co-authored-by: stijn <stijn@ignitron.net> Signed-off-by: Alessandro Gatti <a.gatti@frob.it>
85 lines
1.9 KiB
Python
85 lines
1.9 KiB
Python
try:
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import re
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except ImportError:
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print("SKIP")
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raise SystemExit
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try:
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re.sub
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except AttributeError:
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print("SKIP")
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raise SystemExit
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import sys
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def multiply(m):
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return str(int(m.group(0)) * 2)
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print(re.sub(r"\d+", multiply, "10 20 30 40 50"))
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print(re.sub(r"\d+", lambda m: str(int(m.group(0)) // 2), "10 20 30 40 50"))
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def A():
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return "A"
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print(re.sub("a", A(), "aBCBABCDabcda."))
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print(
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re.sub(
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r"def\s+([a-zA-Z_][a-zA-Z_0-9]*)\s*\(\s*\):",
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"static PyObject*\npy_\\1(void){\n return;\n}\n",
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"\n\ndef myfunc():\n\ndef myfunc1():\n\ndef myfunc2():",
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)
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)
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print(
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re.compile("(calzino) (blu|bianco|verde) e (scarpa) (blu|bianco|verde)").sub(
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r"\g<1> colore \2 con \g<3> colore \4? ...", "calzino blu e scarpa verde"
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)
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)
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# \g immediately followed by another \g
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print(re.sub("(abc)", r"\g<1>\g<1>", "abc"))
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# no matches at all
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print(re.sub("a", "b", "c"))
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# with maximum substitution count specified
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if sys.implementation.name != "micropython":
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# On CPython 3.13 and later the substitution count must be a keyword argument.
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print(re.sub("a", "b", "1a2a3a", count=2))
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else:
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print(re.sub("a", "b", "1a2a3a", 2))
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# invalid group
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try:
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re.sub("(a)", "b\\2", "a")
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except:
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print("invalid group")
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# invalid group with very large number (to test overflow in uPy)
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try:
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re.sub("(a)", "b\\199999999999999999999999999999999999999", "a")
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except:
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print("invalid group")
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# Module function takes str/bytes/re.
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print(re.sub("a", "a", "a"))
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print(re.sub(b".", b"a", b"a"))
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print(re.sub(re.compile("a"), "a", "a"))
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try:
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re.sub(123, "a", "a")
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except TypeError:
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print("TypeError")
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# Include \ in the sub replacement
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print(re.sub("b", "\\\\b", "abc"))
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# Using ^, make sure it doesn't repeatedly match
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print(re.sub("^ab", "*", "abababcabab"))
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print(re.sub("^ab|cab", "*", "abababcabab"))
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